Question 3.2.2: Additional Answer Options

3.1

Motion of an object under the influence of the gravitational force only.   

Or

Motion in which the only force acting on the object is the gravitational force.  

  Tips: 

• Free fall and vertical projectile motion both describe the motion of an object when the only force acting on the object is the gravitational force.
• If your response focuses on the object rather than its motion, you will lose the mark.
• As of 2024, you will not be awarded marks for using the term 'weight' or 'gravity', you need to refer to gravitational force.

2 marks

(1 x 2 marks)

3.2.1

Δt = 0,67 – 0,64 = 0,03 s

Tip: the time that the ball is in contact with the floor, is the time when the position is zero as shown in the graph below:

2 marks

(1 x 2 marks)

3.2.2

Option 1

Tips: 

• The time that it takes for the ball to reach the maximum height from its projection is equal to the time it takes for the ball to return from that height back to the point of projection. Therefore, divide the time by 2.

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2 marks

(1 x 2 marks)

3.2.3

Option 1

Upwards as positive:

⁽¹⁾

⁽²⁾

⁽³⁾

Or

Downwards as positive:

⁽¹⁾

⁽²⁾

⁽¹⁾

Tip: the ball must move in the opposite direction to the direction of gravity. One value must be positive and the other must be negative.

There are more ways to answer this question. To view other options, click here.

3 marks

(3 x 1 mark)

Marking criteria:

• ⁽¹⁾ Any appropriate formula
• ⁽²⁾ Correct substitution
• ⁽³⁾ Final answer: 5,94 to 6,08 m·s^-1  

3.2.4

How to approach this question: 

• This question provides multiple parts with multiple alternative options.

Part 1:

Option 1

Downwards as positive:

⁽¹⁾

⁽²⁾

Or

Upwards as positive:

⁽¹⁾

⁽²⁾

Part 2:

Option 1

Upwards as positive:

⁽³⁾

⁽⁴⁾

⁽⁵⁾

⁽⁶⁾

Or

⁽³⁾

⁽⁴⁾

^{(5 + 6)}

Or

Downwards as positive:

⁽³⁾

⁽⁴⁾

⁽⁵⁾

⁽⁶⁾

• Each mark can only be awarded once.

There are more ways to answer this question. To view other options, click here.

6 marks

(6 x 1 mark)

Option 1/2/3/4 marking criteria:

Calculating initial velocity:

• ⁽¹⁾ Appropriate formula
• ⁽²⁾ Substitution

Calculating Δt:

• ⁽³⁾ Appropriate formula
• ⁽⁴⁾ Substitution
• ⁽⁵⁾ 1,97 s + Δt
• ⁽⁶⁾ Final answer: 2,95 – 2,97 s